Mg+H2SO4→MgSO4+H2
nMg=12/24=0,5mol
nH2SO4=0,5mol
nH2SO4 lấy=0,5+0,5.15/100=0,575mol
mH2SO4=0,575.98=56,35g
mdd H2SO4=56,35.100/19,6=287,5g
mdd spứ=12+287,5-0,5.2=298,5
mMgSO4=0,5.120=60g
C%MgSO4=60/298,5.100%=20,1%
b) mdd H2SO4=287,5g
Vdd H2SO4=mdd/D=287,5/1,12=256,7ml