Đáp án đúng: C
0,288 gam
Ta quy đổi hh về FeO và Fe2O3:
$\begin{array}{l}FeO+2HCl\to FeC{{l}_{2}}+{{H}_{2}}O\\0,009\text{ }\,\,\,\,\,\leftarrow \,\,\,\,\,\,\,\,\,\,0,009\end{array}$
$\Rightarrow m\left( F{{e}_{2}}{{O}_{3}} \right)=1,368-72.0,009=0,72gam\\\Rightarrow n\left( F{{e}_{2}}{{O}_{3}} \right)=0,72:160=0,0045$
$\begin{array}{l}F{{e}_{2}}{{O}_{3}}+6HCl\to 2FeC{{l}_{3}}+3{{H}_{2}}O\\0,0045\text{ }\,\,\,\,\,\,\,\,\,\,\,\to\,\,\,\,\,\,\,\, \text{ 0,009}\end{array}$
$\begin{array}{l}2FeC{{l}_{3}}+Cu\to 2FeC{{l}_{2}}+CuC{{l}_{2}}\\\text{0,009}\,\to \,\text{0,0045}\\\Rightarrow \,{{\text{m}}_{\text{Cu}}}\,\text{=}\,\text{0,288}\,\text{gam}\end{array}$