Đáp án:
$\dfrac{{{p_1}}}{{{p_2}}} = \sqrt {\dfrac{{{m_1}}}{{{m_2}}}} $
Giải thích các bước giải:
Ta có:
$\begin{array}{l}
{W_{d1}} = \dfrac{1}{2}{m_1}{v_1}^2 = \dfrac{1}{2}\dfrac{{{m_1}^2{v_1}^2}}{{{m_1}}} = \dfrac{{{p_1}^2}}{{2{m_1}}}\\
{W_{d2}} = \dfrac{1}{2}{m_2}{v_2}^2 = \dfrac{1}{2}\dfrac{{{m_2}^2{v_2}^2}}{{{m_2}}} = \dfrac{{{p_2}^2}}{{2{m_2}}}\\
{W_{d1}} = {W_{d2}} \Leftrightarrow \dfrac{{{p_1}^2}}{{2{m_1}}} = \dfrac{{{p_2}^2}}{{2{m_2}}} \Leftrightarrow {\left( {\dfrac{{{p_1}}}{{{p_2}}}} \right)^2} = \dfrac{{{m_1}}}{{{m_2}}} \Rightarrow \dfrac{{{p_1}}}{{{p_2}}} = \sqrt {\dfrac{{{m_1}}}{{{m_2}}}}
\end{array}$
