a,
$[SO_4^{2-}]=0,005M$
$[H^+]=0,005.2=0,01M$
$\Rightarrow pH=-\lg[H^+]=2$
b,
$n_{H^+}=0,01.0,2=0,002(mol)$
$[OH^-]=10^{-pOH}=10^{-2}=0,01M$
$\Rightarrow n_{OH^-}=0,01.0,3=0,003(mol)$
$\Rightarrow n_{OH^-\text{dư}}=0,003-0,002=0,001(mol)$
$[OH^-]=\dfrac{0,001}{0,3+0,2}=0,002M$
$\Rightarrow pH=14-pOH=14+\lg[OH^-]=11,3$