`a`
`R+Cl_2 → RCl_2`
`n_R= n_{RCl_2}`
`<=> {3,2}/R = {6,75}/{R + 71}`
`→ R = 64`$(g/mol)$
`→ R: Cu`
`n_{Cl_2} = n_{Cu} = {3,2}/{64} = 0,05(mol)`
`2KMnO_4 + 16HCl → 2KCl + 2MnCl_2 + 5Cl_2 + 8H_2O`
`n_{KMnO_4} = 2n_{Cl_2} = 0,02(mol)`
`m= 0,02. 158 = 3,16(g)`
`n_{HCl} ={16}/5n_{Cl_2} =0,16(mol)`
`mdd_{HCl} = {0,16 . 36,5}/{37%} = {584}/{37} (g)`
`Vdd = {584}/{37} : 1,19 = 13,26(ml)`