Lời giải:
Đặt `\frac{x}{3}=\frac{y}{5}=k`
`⇒`$\left \{ {{x=3k} \atop {y=5k}} \right.$
Do đó:`A=\frac{5x^2+3y^2}{10x^2-3y^2}`
`⇒A=\frac{5×9k^2+3×25k^2}{10×9k^2-3×25k^2}`
`⇒A=\frac{45k^2+75k^2}{90k^2-75k^2}`
`⇒A=\frac{k^2(45+75)}{k^2(90-75)}`
`⇒A=\frac{k^2×120}{k^2×15}`
`⇒A=\frac{120}{15}`
`⇒A=8`