Mg + 2HCl ==> MgCl2 + H2
0,2..........0,4......................................0,2
CuO + 2HCl ==> CuCl2 + H2O
0,3325...0,665
Ta có: nH2= 4,48/22,4= 0,2 (mol)
==> mMg= 0,2x24= 4,8 (g)
==> mCuO= 31,4-4,8= 26,6 (g)
==> nCuO= 26,6/80= 0,3325 (mol)
nHCl= 0,665 + 0,4= 1,065 (mol)
==> CmHCl= n/V= 1,065/0,5= 2,13M