`n_{\text{hh khí}}=\frac{5,6}{22,4}=0,25(mol)`
`n_{Br_2}=\frac{5,6}{160}=0,035(mol)`
`a)` Phương trình:
`CH_2=CH_2+Br_2\to CH_2Br-CH_2Br`
`=> n_{C_2H_4}=n_{Br_2}=0,035(mol)`
`=> n_{CH_4}=0,25-0,035=0,215(mol)`
`b) ` `%V_{CH_4}=\frac{0,215.100%}{0,25}=86%`
`%V_{C_2H_4}=\frac{0,035.100%}{0,25}=14%`