$a/$ $Zn$ $+$ $2HCl$ → $ZnCl_{2}$ $+$$H_{2}$
$b/$$n_{Zn}$ $=$$\frac{6.5}{65}$ $=$$0,1$($mol$)
$n_{HCl}$ = $2.0.1$=$0,2$ ($mol$)
$m_{HCl}$ =$0.2 . 36,5$=$7.3$($g$)
$c/$$n_{H2}$ =$n_{Zn}$ =$0,1$ $mol$
$V_{H2(đktc)}$ = $0,1.22,4$ =$2.24$ ($lít$)
$d/$$n_{ZnCl2}$ =$n_{Zn}$ =$0,1$ $mol$
$m_{ZnCl2}$ =$0,1.136$=$13,6$ ($g$)