Đáp án đúng: A
1,12 lít.
$\begin{array}{l}\,\,\,\,\,3Cu\,\,\,\,\,+\,\,\,\,\,\,8HN{{O}_{3}}\xrightarrow{{}}3Cu{{(N{{O}_{3}})}_{2}}+2NO+4{{H}_{2}}O\\\frac{6,4}{64}=0,1\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\xrightarrow{{}}\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\frac{1}{15}\end{array}$
$\begin{array}{l}2NO+{{O}_{2}}\xrightarrow{{}}2N{{O}_{2}}\\\frac{1}{15}\,\,\to \,\frac{1}{30}\,\,\,\,\xrightarrow{{}}\,\,\,\,\frac{1}{15}\\2N{{O}_{2}}+\frac{1}{2}{{O}_{2}}+{{H}_{2}}O\xrightarrow{{}}2HN{{O}_{3}}\\\frac{1}{15}\,\,\,\to \,\,\frac{1}{60}\end{array}$
$\Rightarrow {{V}_{{{O}_{2}}}}=(\frac{1}{30}+\frac{1}{60}).22,4=1,12\,l$