A = 1 + 2 + $2^{2}$ + $2^{3}$ + ... + $2^{9}$
2A = 2 + $2^{2}$ + $2^{3}$ + ... + $2^{10}$
2A - A = (2 + $2^{2}$ + $2^{3}$ + ... + $2^{10}$) - (1 + 2 + $2^{2}$ + $2^{3}$ + ... + $2^{9}$)
A = $2^{10}$ - 1
A = 1024 - 1
A = 1023
Ta có: 5 . 28 = 140
Vì 1023 > 140 nên A > 5 . 28