$Áp dụng BĐT svac-xơ ta có:$
$\frac{1}{a}$ + $\frac{1}{b}$ + $\frac{4}{c}$ +$\frac{16}{d}$ ≥$\frac{(1+1+2+4)mũ 2}{a+b+c+d}$ =$\frac{64}{a+b+c+d}$
$Dấu = xảy ra khi $ $\frac{1}{a}$ =$\frac{1}{b}$ =$\frac{2}{c}$ =$\frac{4}{d}$
<=> $a=b=$ $\frac{c}{2}$ =$\frac{d}{4}$