`a)`
ĐKXĐ : ` x \ne 2 ; \ x \ne -2`
`b)`
` A = (x^2)/(x^2-4)- x/(x-2) -2/(x+2)`
` = (x^2)/((x-2)(x+2)) - (x(x+2))/((x-2)(x+2)) - (2(x-2))/((x-2)(x+2))`
` = (x^2 - x^2 -2x -2x +4)/((x-2)(x+2))`
` = ( -4x +4)/((x-2)(x+2))`
`c)`
Thay ` x = 1` ta có
` A = ( -4x +4)/((x-2)(x+2)) = ( -4 . 1 +4)/(1^2-4) = 0`