Bài giải
a, Ta có :
c = 2+2$^{2}$ + 2$^{3}$+2$^{4}$ + 2$^{5}$ + ... +2$^{100}$
c = ( 2+2$^{2}$ + 2$^{3}$+2$^{4}$ + 2$^{5}$ ) + ... + ( 2$^{96}$ + 2$^{97}$+2$^{98}$+ 2$^{99}$+2$^{100}$ )
c = 2( 1+2 +2$^{2}$ + 2$^{3}$+2$^{4}$ ) + ... + 2^96 ( 1+2 +2$^{2}$ + 2$^{3}$+2$^{4}$ )
c = 2 . 31 + ... + $2^{96}$ . 31
c = 31 ( 2 + ... + $2^{96}$ ) chia hết cho 31