Đáp án:
$\begin{array}{l}
m = 1\\
\Rightarrow y = x - 1\\
+ Khi:x = - 1 \Rightarrow y = - 1 - 1 = - 2\\
\Rightarrow A\left( { - 1; - 2} \right)\\
+ Khi:x = 2 \Rightarrow y = 2 - 1 = 1\\
\Rightarrow B\left( {2;1} \right)\\
\Rightarrow AB = \sqrt {{{\left( {2 + 1} \right)}^2} + {{\left( {1 + 2} \right)}^2}} = 3\sqrt 2 \\
\left( d \right):y = x - 1\\
+ Cho:x = 0 \Rightarrow y = - 1\\
+ Cho:y = 0 \Rightarrow x = 1\\
\Rightarrow {d_{o - \left( d \right)}} = \dfrac{1}{{\sqrt 2 }} = \dfrac{{\sqrt 2 }}{2}\\
\Rightarrow {S_{AOB}} = \dfrac{1}{2}.d.AB = \dfrac{1}{2}.\dfrac{{\sqrt 2 }}{2}.3\sqrt 2 = \dfrac{3}{2}
\end{array}$
