Đáp án:
\(\begin{array}{l}
1.\\
R = 6\Omega \\
I = 2,2A\\
2.\\
R = \frac{6}{{11}}\Omega \\
I = 24,2A\\
3.R = 2,2\Omega \\
I = 6A
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
1.\\
R = {R_1} + {R_2} + {R_3} = 1 + 2 + 3 = 6\Omega \\
I = \frac{U}{R} = \frac{{13,2}}{6} = 2,2A\\
2.\\
\frac{1}{R} = \frac{1}{{{R_1}}} + \frac{1}{{{R_2}}} + \frac{1}{{{R_2}}} = \frac{1}{1} + \frac{1}{2} + \frac{1}{3} = \frac{{11}}{6}\\
\Rightarrow R = \frac{6}{{11}}\Omega \\
I = \frac{U}{R} = \frac{{13,2}}{{\frac{6}{{11}}}} = 24,2A\\
3.\\
{R_{23}} = \frac{{{R_2}{R_3}}}{{{R_2} + {R_3}}} = \frac{{2.3}}{{2 + 3}} = 1,2\Omega \\
R = {R_1} + {R_{23}} = 1,2 + 1 = 2,2\Omega \\
I = \frac{U}{R} = \frac{{13,2}}{{2,2}} = 6A
\end{array}\)