Đáp án:
$\widehat{BOC}$ = $\widehat{AOD}$ = $120^{o}$
$\widehat{BOD}$ = $\widehat{AOC}$ = $60^{o}$
Giải thích các bước giải:
Ta có : $\widehat{BOC}$ + $\widehat{BOD}$ = $180^{o}$
`=> 2 .` $\widehat{BOD}$ `+` $\widehat{BOD}$ `=` $180^{o}$ ( Do $\widehat{BOC}$ `= 2 .` $\widehat{BOD}$ )
`=> 3 .` $\widehat{BOD}$ `=` $180^{o}$
`=>` $\widehat{BOD}$ `=` $60^{o}$
`=>` $\widehat{BOC}$ `=` $180^{o}$ `-` $60^{o}$ `=` $120^{o}$
Ta thấy : $\widehat{BOC}$ `=` $\widehat{AOD}$ `=` $120^{o}$ ( hai góc đối đỉnh )
$\widehat{BOD}$ `=` $\widehat{AOC}$ `=` $60^{o}$ ( hai góc đối đỉnh )
Vậy $\widehat{BOC}$ `=` $\widehat{AOD}$ `=` $120^{o}$
$\widehat{BOD}$ = $\widehat{AOC}$ `=` $60^{o}$