Cho đường tròn \(\left( C \right):\,\,\,{\left( {x - 2} \right)^2} + {\left( {y - 1} \right)^2} = 20.\) Lập phương trình tiếp tuyến của đường tròn \(\left( C \right)\) có hệ số góc bằng \(2.\)
A.\(\left[ \begin{array}{l}{\Delta _1}:\,\,\,2x - y + 7 = 0\\{\Delta _2}:\,\,\,2x - y - 13 = 0\end{array} \right.\)
B.\(\left[ \begin{array}{l}{\Delta _1}:\,\,\,2x - y - 7 = 0\\{\Delta _2}:\,\,\,2x - y - 13 = 0\end{array} \right.\)
C.\(\left[ \begin{array}{l}{\Delta _1}:\,\,\,2x - y - 7 = 0\\{\Delta _2}:\,\,\,2x - y + 13 = 0\end{array} \right.\)
D.\(\left[ \begin{array}{l}{\Delta _1}:\,\,\,2x - y + 7 = 0\\{\Delta _2}:\,\,\,2x - y + 13 = 0\end{array} \right.\)
A.\(\left[ \begin{array}{l}{\Delta _1}:\,\,\,2x - y + 7 = 0\\{\Delta _2}:\,\,\,2x - y - 13 = 0\end{array} \right.\)
B.\(\left[ \begin{array}{l}{\Delta _1}:\,\,\,2x - y - 7 = 0\\{\Delta _2}:\,\,\,2x - y - 13 = 0\end{array} \right.\)
C.\(\left[ \begin{array}{l}{\Delta _1}:\,\,\,2x - y - 7 = 0\\{\Delta _2}:\,\,\,2x - y + 13 = 0\end{array} \right.\)
D.\(\left[ \begin{array}{l}{\Delta _1}:\,\,\,2x - y + 7 = 0\\{\Delta _2}:\,\,\,2x - y + 13 = 0\end{array} \right.\)
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Hóa Học lớp 12
