Cho \( \left( E \right): \, \, \dfrac{{{x^2}}}{9} + \dfrac{{{y^2}}}{1} = 1 \). Tìm \(M \) có tọa độ dương thuộc \( \left( E \right) \) để \(M{F_1} = 2M{F_2} \).
A.\(\left( {\dfrac{{3\sqrt 2 }}{4};\dfrac{{\sqrt {14} }}{4}} \right)\)
B.\(\left( {\dfrac{3}{{14}};\dfrac{1}{{14}}} \right)\)
C.\(\left( {\dfrac{{\sqrt 2 }}{4};\dfrac{{\sqrt {14} }}{4}} \right)\)
D.\(\left( {\dfrac{{3\sqrt 2 }}{4};\dfrac{1}{4}} \right)\)
A.\(\left( {\dfrac{{3\sqrt 2 }}{4};\dfrac{{\sqrt {14} }}{4}} \right)\)
B.\(\left( {\dfrac{3}{{14}};\dfrac{1}{{14}}} \right)\)
C.\(\left( {\dfrac{{\sqrt 2 }}{4};\dfrac{{\sqrt {14} }}{4}} \right)\)
D.\(\left( {\dfrac{{3\sqrt 2 }}{4};\dfrac{1}{4}} \right)\)
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Hóa Học lớp 12
