Cho hàm số \[y=f(x)=\sqrt{1+{{\cos }^{2}}2x}\]. Chọn kết quả đúng.
A.\[\text{d}f(x)=\dfrac{-\sin 2x}{\sqrt{1+{{\cos }^{2}}2x}}\text{d}x\].
B.\[\text{d}f(x)=\dfrac{\cos 2x}{\sqrt{1+{{\cos }^{2}}2x}}\text{d}x\].
C.$\text{d}f(x)=\dfrac{-\sin 4x}{\sqrt{1+{{\cos }^{2}}2x}}\text{d}x$.
D.$\text{d}f(x)=\dfrac{-\sin 4x}{2\sqrt{1+{{\cos }^{2}}2x}}\text{d}x$.