Pt có 1 nghiệm
$→\dfrac{m}{m³}\ne \dfrac{-1}{m²-1}$
$→\dfrac{1}{m²}\ne \dfrac{-1}{m²-1}$
$→m²=1-m²$
$→2m²=1$
$→m²=\dfrac{1}{2}$
$→m=\dfrac{1}{\sqrt 2}\quad or\quad -\dfrac{1}{\sqrt 2}$
Pt vô nghiệm
$→\dfrac{1}{m²}=\dfrac{-1}{m²-1}\ne \dfrac{1}{2}$
$\dfrac{1}{m²}=\dfrac{1}{1-m²}$
$→m²=1-m²$
$→m=\dfrac{1}{\sqrt 2}\quad or\quad m=-\dfrac{1}{\sqrt 2}$
$\dfrac{1}{m²}\ne \dfrac{1}{2}$
$→m²\ne 2$
$→m\ne \sqrt 2\quad or\quad m\ne -\sqrt 2$
Pt vô số nghiệm
$→\dfrac{1}{m²}=\dfrac{-1}{m²-1}=\dfrac{1}{2}$
$\dfrac{1}{m²}=\dfrac{1}{2}$
$→m=\sqrt 2\quad or\quad m=-\sqrt 2$ (1)
$\dfrac{-1}{m²-1}=\dfrac{1}{2}$
$→m²-1=-2$
$→m²=-1$ (vô lý) (2)
(1)(2) $→m∈\{\varnothing\}$
