$\Delta ABC$ vuông tại $A$
$\Rightarrow AC=\sqrt{BC^2-AB^2}=12cm\\ AA'=BB'=CC'=17\\ S_{AA'C'C}=AA'.AC=204(cm^2)\\ S_{BB'C'C}=BB'.BC=255(cm^2)\\ S_{AA'B'B}=AA'.AB=153(cm^2)\\ S_{ABC}=S_{A'B'C'}=\dfrac{1}{2}AB.AC=54(cm^2)\\ S_{xq}=S_{AA'C'C}+S_{BB'C'C}+S_{AA'B'B}=612cm^2\\ S_{tp}=S_{xq}+2S_{ABC}=720cm^2\\ V=S_{ABC}.AA'=918cm^3$