Giải thích các bước giải:
Gọi $AD\cap BC=I\to \dfrac{IA}{ID}=\dfrac{IB}{IC}=\dfrac{3}{7}$
$\to \dfrac{AI}{AI+ID}=\dfrac{IB}{IB+IC}=\dfrac{3}{3+7}$
$\to \dfrac{AI}{AD}=\dfrac{IB}{BC}=\dfrac{3}{10}$
$\to AI=\dfrac{3}{10}AD=\dfrac{12}{5}, BI=\dfrac{3}{10}BC=\dfrac{9}{5}$
$\to AI^2+BI^2=9=AB^2(\text{ theo Pitago })\to AI\perp IB\to AD\perp BC$