$\begin{array}{l}Fe+2HCl \to FeCl_2+H_2\\Zn+2HCl \to ZnCl_2+H_2\end{array}$
$\begin{cases} n_{Fe}=xmol\\n_{Zn}=ymol\end{cases}$
$\begin{array}{l} n_{HCl}=2.0,25=0,5mol=x+y\\m_{hh}=56x+65y=14,9\end{array}$
$\begin{cases} x+y=0,25\\56x+65y=14,9\end{cases}$
$\begin{cases} x=0,15mol\\y=0,1mol\end{cases}$
$\begin{array}{l} \%m_{Fe}=\dfrac{0,15.56}{14,9\%}=56,38\%\\ \%m_{Zn}=100\%-56,38\%=43,62\%\\n_{H_2}=0,15+0,1=0,25mol\\V_{H_2}=0,25.22,4=5,6l\end{array}$