Zn + 2HCl => ZnCl2 + H2
a) nZnCl2=2,72/136=0,02 (mol)
=> nZn=nZnCl2=0,02 (mol) => mZn=0,02.65=1,3 (g)
b) nH2=nZnCl2=0,02 (mol) => VH2=0,02.22,4=0,448 (l)
c) 2H2 + 2O2 =nhiệt độ=> 2H2O (1)
CH4 + 2O2 =nhiệt độ=> CO2 + 2H2O (2)
nH2O= 0,54/18=0,03 (mol)
nH2O (1)=nH2=0,02 (mol)
=> nH2O (2)=0,03-0,02=0,01 (mol) => nCH4=1/2nH2O (2)= (1/2),0,01=0,005 (mol)
=> VCH4=0,005.22,4=0,112 (l)