Gọi x, y là mol $Na_2CO_3$, $BaCO_3$
$\%O=33,71\%$
$\Rightarrow \dfrac{16.(3x+3y).100}{106x+197y}=33,71$
$\Rightarrow 1600(3x+3y)=33,71(106x+197y)$
$\Leftrightarrow 1226,74x-1840,87y=0$ (1)
$Na_2CO_3+2HCl\to 2NaCl+CO_2+H_2O$
$BaCO_3+2HCl\to BaCl_2+CO_2+H_2O$
$\Rightarrow 22,4x+22,4y=4,48$ (2)
(1)(2)$\Rightarrow x=0,12; y=0,08$
$\Rightarrow m=0,12.106+0,08.197=28,48g$
$\Rightarrow$ B