Đáp án:
\[\begin{array}{l}
\dfrac{{k{T_2}}}{{k{T_1}}} = \dfrac{{(2{m_1}{c_1} + {m_2}{c_2})\Delta t}}{{({m_1}{c_1} + {m_2}{c_2})\Delta t}}\\
\Rightarrow \dfrac{{{T_2}}}{{{T_1}}} = \dfrac{{2{m_1}{c_1} + {m_2}{c_2}}}{{{m_1}{c_1} + {m_2}{c_2}}} = \dfrac{{{m_1}{c_1} + {m_1}{c_1} + {m_2}{c_2}}}{{{m_1}{c_1} + {m_2}{c_2}}} = \dfrac{{{m_1}{c_1}}}{{{m_1}{c_1} + {m_2}{c_2}}} + 1
\end{array}\]