Đáp án:
a. \(40°\)
b. \(\widehat{xOm}>\widehat{yOm}\)
Giải thích các bước giải:
a.
Do \(Om \perp Ox\) nên \(\widehat{xOm}=90°\)
Ta có: \(\widehat{xOy}=\widehat{xOm}+\widehat{mOy}\)
\(\Leftrightarrow 140°=90°+\widehat{mOy}\)
\(\Rightarrow \widehat{mOy}=140°-90°=50°\)
Do \(On \perp Oy\) nên \(\widehat{yOn}=90°\)
Ta có: \(\widehat{xOy}=\widehat{yOn}+\widehat{nOx}\)
\(\Leftrightarrow 140°=90°+\widehat{nOx}\)
\(\Rightarrow \widehat{nOx}=140°-90°=50°\)
Ta có: \(\widehat{mOn}+\widehat{mOy}+\widehat{nOx}=\widehat{xOy}=180°\)
\(\Leftrightarrow \widehat{mOn}=140°-50°-50°=40°\)
b.
\(\widehat{xOm}=90°\)
\(\widehat{yOm}=50°\)
\(\Rightarrow \widehat{xOm}>\widehat{yOm}\)
