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Đáp án:
ĐKXĐ: $x ≠ - 2; x ≠ 2$
$P = (\dfrac{x + 2}{2x - 4} + \dfrac{x - 2}{2x + 4} + \dfrac{- 8}{x^2 - 4}) : \dfrac{4}{x - 2}$
$= \dfrac{(x + 2)^2 + (x - 2)^2 - 2.8}{2(x - 2)(x + 2)} . \dfrac{x - 2}{4}$
$= \dfrac{x^2 + 4x + 4 + x^2 - 4x + 4 - 16}{8(x + 2)}$
$= \dfrac{2(x^2 - 4)}{8(x + 2)}$
$= \dfrac{(x - 2)(x + 2)}{4(x + 2)}$
$= \dfrac{x - 2}{4}$
