cho parabol (P) : y = $\frac{1}{4}$ x² ; Và đuòng thẳng (d) : y = $\frac{-1}{2}$x + 2 a) Vẽ (P) và (d) trên cùng 1 hệ trục toạ độ b) Gọi A và B là giao điểm của (d) và (P) . Tìm toạ độ A ,B

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