Cho phương trình hóa học sau: 2Al + 6HCl → 2AlCl3 + 3H2. Quá trình khử là
A.\(\mathop {Al}\limits^0 \to \mathop {Al}\limits^{ + 3} + 3{\rm{e}}\)
B.\(\mathop {Al}\limits^{ + 3} + 3{\rm{e}} \to \mathop {Al}\limits^0 \)
C.\(2\mathop H\limits^{ + 1} + 2{\rm{e}} \to {\mathop H\limits^0 _2}\)
D.\(2\mathop H\limits^{ + 1} \to {\mathop H\limits^0 _2} + 2{\rm{e}}\)
A.\(\mathop {Al}\limits^0 \to \mathop {Al}\limits^{ + 3} + 3{\rm{e}}\)
B.\(\mathop {Al}\limits^{ + 3} + 3{\rm{e}} \to \mathop {Al}\limits^0 \)
C.\(2\mathop H\limits^{ + 1} + 2{\rm{e}} \to {\mathop H\limits^0 _2}\)
D.\(2\mathop H\limits^{ + 1} \to {\mathop H\limits^0 _2} + 2{\rm{e}}\)
Loga
Hóa Học lớp 12
