Đáp án+Giải thích các bước giải:
`sin^2\alpha+cos^2\alpha=1`
`⇔cos\alpha=\sqrt{1-sin^2\alpha}`
`⇔cos\alpha=\sqrt{1-(\frac{\sqrt{3}}{2})^2}`
`⇔cos\alpha=\frac{1}{2}`
`tan\alpha=\frac{sin\alpha}{cos\alpha}`
`⇔tan\alpha=\frac{\sqrt{3}}{2}:\frac{1}{2}`
`⇔tan\alpha=\sqrt{3}`
`cot\alpha=\frac{1}{tan\alpha}`
`⇔cot\alpha=\frac{1}{\sqrt{3}}=\frac{\sqrt{3}}{3}`
Vậy $\begin{cases}cos\alpha=\dfrac{1}{2}\\tan\alpha=\sqrt{3}\\cot\alpha=\dfrac{\sqrt{3}}{3}\end{cases}$
