Đáp án:
$\begin{array}{l}
co:\cos C = \frac{{HC}}{{AC}} \Rightarrow c{\rm{os6}}{{\rm{0}}^0} = \frac{6}{{AC}} \Rightarrow AC = \frac{6}{{cos{{60}^0}}} = 12\left( {cm} \right)\\
\tan C = \frac{{AB}}{{AC}} \Rightarrow \sqrt 3 = \frac{{AB}}{{12}} \Rightarrow AB = 12\sqrt 3 \left( {cm} \right)
\end{array}$