Đáp án:
`(x^3-9x)(2x^2-5x+2)=0`
`⇒x(x²-9)(2x^2-5x+2)=0`
`⇒x(x²-3²)(2x^2-5x+2)=0`
`⇒x(x²-3²)(2x^2-4x-x+2)=0`
`⇒x(x-3)(x+3)[2x(x-2)-1(x-2)]=0`
`⇒x(x-3)(x+3)(2x-1)(x-2)=0`
`⇒`\(\left[ \begin{array}{l}x=0\\x=-3\\x=3\\x=\frac{1}{2}\\x=2\end{array} \right.\)
`⇒`Chọn `B.A{0,2,3}`
@Star