Đặt `a/b=c/d=k`
`=>a=bk; c=dk`
Thay vào `(5a-3b)/(3a+2b); (5c-3d)/(3c+2d)` ta được:
`(5a-3b)/(3a+2b)=(5bk-3b)/(3bk+2b)=[b(5k-3)]/[b(3k+2)]=(5k-3)/(3k+2)`
`(5c-3d)/(3c+2d)=(5dk-3d)/(3dk+2d)=[d(5k-3)]/[d(5k+2)]=(5k-3)/(3k+2)`
`=> (5a-3b)/(3a+2b) = (5c-3d)/(3c+2d) `