`nAl (OH) 3=7,878=0,1(mol)7,878=0,1 (mol)`
Để Vdd NaOH là lớn nhất thì :
`2NaOH+ H2SO4→ Na2SO4+ 2H2O2NaOH+ H2SO4→ Na2SO4+ 2H2O`
`0,2_________0,1_____________________(mol)`
`6` `NaOH+ Al2(SO4)3→ 3Na2SO4+ 2Al(OH)3↓6NaOH+ Al2(SO4)3→ 3Na2SO4+ 2Al(OH)3↓`
`0,6_______0,1______________________0,2______(mol)`
`NaOH+ Al(OH)3→ NaAlO2+ H2O`
`0,1P______0,1______________________(mol)`
`→VddNaOH=0,1+0,6+0,12=0,4l`
Xin hay nhất !