Giải thích các bước giải:
a.Ta có :
$x^2+2\quad\vdots\quad x+2$
$\to x^2-4+6\quad\vdots\quad x+2$
$\to x^2-2^2+6\quad\vdots\quad x+2$
$\to (x+2)(x-2)+6\quad\vdots\quad x+2$
$\to 6\quad\vdots\quad x+2$
$\to x+2\in\{1,2,3,6,-1,-2,-3,-6\}$
$\to x\in\{-1,0,1,4,-2,-4,-5,-8\}$
b.$x^2-2x+3\quad\vdots\quad x-1$
$\to x^2-2x+1+2\quad\vdots\quad x-1$
$\to (x-1)^2+2\quad\vdots\quad x-1$
$\to 2\quad\vdots\quad x-1$
$\to x-1\in\{1,2,-1,-2\}$
$\to x\in\{2,3,0,-1\}$