Đáp án:
$(\dfrac{√a+√b}{√a-√b}-$ $\dfrac{√a-√b}{√a+√b}):$ $\dfrac{√ab}{a-b}$
$=$ $\dfrac{(√a+√b)^2-(√a-√b)^2}{(√a-√b)(√a+√b)}:$ $\dfrac{√ab}{a-b}$
$=$ $\dfrac{a+2√ab+b-(a-2√ab+b)}{√a^2-√b^2}.$ $\dfrac{a-b}{√ab}$
$=$ $\dfrac{a+2√ab+b-a+2√ab-b}{a-b}.$ $\dfrac{a-b}{√ab}$
$=$ $\dfrac{4√ab}{a-b}.$ $\dfrac{a-b}{√ab}$ $= 4$
(Điều kiện: $a>0$ ; $b>0$ ; $a$$\neq$$b$)
BẠN THAM KHẢO NHA!!!