Giải thích các bước giải:
`1/2^2 + 1/3^2 + 1/4^2 + ... + 1/2011^2`
`Ta` `thấy` `:` `1/2^2 = 1/4` ; `1/3² < 1/(2 . 3)` ; .......... ; `1/2011² < 1/2010.2011`
`→ A < 1/(1.3) + 1/(2.3) + ..... + 1/(2010.2011)`
`→ A < 1/2² + 1/2 - 1/3 + 1/3 - ..... + 1/2010 - 1/2011`
`→ A < 1/4 + 1/2 - 1/2011`
`→ A < 3/4 - 1/2011 < 3/4`
`→ A < 3/4 (đpcm)`