Bài 1
3`2/5` = `{3 × 5 + 2}/5` = `17/5`
1`4/9` = `{1 × 9 + 4}/9` = `13/9`
15`1/10` = `{15 × 10 + 1}/10` = `151/10`
7`3/8` = `{7 × 8 + 3}/8` = `59/8`
Bài 2
a ) 3`5/9` < 2`7/9`
=> S ; 3 > 2 nên 3`5/9` > 2`7/9`
b ) 5`4/10` = 5`2/5`
=> Đ ; `2/5` = `4/10` nên 5`4/10` = 5`2/5`
c ) 1`2/3` > 1`3/5`
=> Đ ; `2/3` > `3/5` nên 1`2/3` > 1`3/5`
d ) 4`1/8` < 3`3/4`
=> S ; 4 > 3 nên 4`1/8` > 3`3/4`
`#cactus`