Đáp án:
\(\begin{array}{l}
B1:\\
d)\left\{ \begin{array}{l}
\dfrac{3}{2} \ge x\\
x \ne - 5
\end{array} \right.\\
f)\forall x\\
g)2 \ge x \ge 1\\
h)x \in \emptyset
\end{array}\)
Giải thích các bước giải:
\(\begin{array}{l}
B1:\\
d)DK:\left\{ \begin{array}{l}
3 - 2x \ge 0\\
x + 5 \ne 0
\end{array} \right.\\
\to \left\{ \begin{array}{l}
\dfrac{3}{2} \ge x\\
x \ne - 5
\end{array} \right.\\
f)DK:{x^2} + 9 > 0\left( {ld} \right)\forall x\\
\to \forall x\\
g)DK:\left\{ \begin{array}{l}
x - 1 \ge 0\\
2 - x \ge 0
\end{array} \right.\\
\to 2 \ge x \ge 1\\
h)DK:\left\{ \begin{array}{l}
3 - x \ge 0\\
x - 4 > 0
\end{array} \right.\\
\to \left\{ \begin{array}{l}
3 \ge x\\
x > 4
\end{array} \right.\left( {KTM} \right)\\
\to x \in \emptyset
\end{array}\)
