\(\int {\dfrac{{5\left( {{x^2} + x} \right)}}{{\sqrt {2x + 1} }}dx} \), \(x > - \dfrac{1}{2}\) bằng:
A.\(\left( {{x^2} + x + 1} \right)\sqrt {2x + 1} + C\)
B.\(\left( {{x^2} - x + 1} \right)\sqrt {2x + 1} + C\)
C.\(\left( {{x^2} + x - 1} \right)\sqrt {2x + 1} + C\)
D.\(\left( {{x^2} - x - 1} \right)\sqrt {2x + 1} + C\)