Đáp án:
${C_{M\,\,NaOH}} = 1,2M$
Giải thích các bước giải:
${n_{S{O_2}}} = \dfrac{{6,72}}{{22,4}} = 0,3\,\,mol$
PTHH:
$\begin{gathered} S{O_2} + 2NaOH \to N{a_2}S{O_3} + {H_2}O\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \hfill \\ 0,3 \to \,\,\,\,\,0,6\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,mol \hfill \\ \to {C_{M\,\,NaOH}} = \frac{{0,6}}{{0,5}} = 1,2M\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\,\, \hfill \\ \end{gathered} $
