Đáp án+ Giải thích các bước giải:
$2) \sqrt{x+1+2\sqrt{x}}$ ĐK: x≥0
$=\sqrt{x+2.\sqrt{x}.1+1}$
$=\sqrt{(\sqrt{x}+1)^2}=\sqrt{x}+1$
$3)\sqrt{x-2+2\sqrt{x-3}}$ ĐK: x≥3
$=\sqrt{x-3+2.\sqrt{x-3}.1+1}$
$=\sqrt{(\sqrt{x-3}+1)^2}=\sqrt{x-3}+1$
$5)\sqrt{2x-1-2\sqrt{2(x-1)}}$ ĐK: x≥1
$=\sqrt{2x-2-2.\sqrt{2(x-1)}.1+1}$
$=\sqrt{(\sqrt{2(x-1)}-1)^2}=|\sqrt{2(x-1)}-1|$
$6)\sqrt{2x++12\sqrt{2x}}$ ĐK: x≥0
$=\sqrt{2x+2.\sqrt{2x}.1+1}$
$=\sqrt{(\sqrt{2x}+1)^2}=\sqrt{2x}+1$
