Đáp án:
Giải thích các bước giải:
$a/$
$A_1 : CH_2=C(CH_3)-COOH$
$A_2 : CH_3OH$
$A : CH_2=C(CH_3)-COOCH_3$
Phương trình hóa học :
$CH_2=C(CH_3)-COOH + CH_3OH \buildrel{{xt}}\over\rightleftharpoons CH_2=C(CH_3)-COOCH_3 + H_2O$
$nCH_2=C(COOCH_3)(CH_3) \xrightarrow{t^o,xt,p} (-CH_2-C(COOCH_3)(CH_3)-)_n$
$2CH_2=C(CH_3)-COOH + CaCO_3 → (CH_2=C(CH_3)-COO)_2Ca + CO_2 + H_2O$
$2CH_2=C(CH_3)-COOH + 2Na → 2CH_2=C(CH_3)-COONa + H_2$
$2CH_3OH + 2Na → CH_3ONa + H_2$
$b/$
$CH_2=C(CH_3)-COOCH_3 + H_2 \xrightarrow{t^o,xt} CH_3-CH(CH_3)-COOCH_3$
$CH_2=C(CH_3)-COOCH_3 + HBr \xrightarrow{t^o} CH_3-CBr(CH_3)-COOCH_3$
$CH_2=C(CH_3)-COOCH_3 + NaOH → CH_2=C(CH_3)-COONa + CH_3OH$
$CH_2=C(CH_3)-COOCH_3 + Br_2 → CH_2Br-CBr(CH_3)-COOCH_3 $