Đáp án:
Giải thích các bước giải:
`CaCO_3+2HCl->CaCl_2+H_2O+CO_2↑`
`CaO+2HCl->CaCl_2+H_2O`
`a.`
`n_{CO_2}=\frac{2,24}{22,4}=0,1(mol)`
`n_{CaCO_3}=n_{CO_2}=0,1(mol)`
`m_{CaCO_3}=0,1.100=10(g)`
`m_{CaO}=21,2-10=11,2(g)`
`%m_{CaCO_3}=\frac{10}{21,2}.100=47,17%`
`%m_{CaO}=\frac{11,2}{21,2}.100=52,83%`
`b.`
`n_{CaO}=\frac{11,2}{56}=0,2(mol)`
`∑n_{HCl}=2.0,1+2.0,2=0,6(mol)`
`m_{HCl}=0,6.36,5=21,9(g)`
`C%_{ddHCl}=\frac{21,9}{200}.100=10,95%`
`m_{ddX}=21,2+200-0,1.44=216,8(g)`
`∑n_{CaCl_2}=0,1+0,2=0,3(mol)`
`m_{CaCl_2}=0,3.111=33,3(g)`
`C%_{ddX}=\frac{33,3}{216,8}.100=15,36%`
`#Devil`