Đáp án:
`h, (x^2 - 4x + 4) - (2x - 3)^2`
`= (x^2 - 2.x.2 + 2^2) - (2x - 3)^2`
`= (x - 2)^2 - (2x - 3)^2`
`= [(x - 2) - (2x - 3)][(x - 2) + (2x - 3)]`
`= (x - 2 - 2x + 3)(x - 2 + 2x - 3)`
`= (-x + 1)(3x - 5)`
`i, x^3 + 6x^2 + 12x - y^3 + 8`
`= (x^3 + 6x^2 + 12x + 8) - y^3`
`= (x^3 + 3.x^2 .2 + 3.x.2^2 + 2^3) - y^3`
`= (x + 2)^3 - y^3`
`= (x + 2 - y)[(x + 2)^2 + (x + 2)y + y^2]`
`= (x + 2 - y)(x^2 + 4x + 4 + xy + 2y + y^2)`
`m, 2y + 3z + 6xy + 9xz`
`= (2y + 3z) + (6xy + 9xz)`
`= (2y + 3z) + 3x(2y + 3z)`
`= (2y + 3z)(1 + 3x)`
`n, 2x^2 + x - 3`
`= 2x^2 - 2x + 3x - 3`
`= (2x^2 - 2x) + (3x - 3)`
`= 2x(x - 1) + 3(x - 1)`
`= (x - 1)(2x + 3)`
`k, 2x^2 - 13x + 15`
`= 2x^2 - 10x - 3x + 15`
`= (2x^2 - 10x) - (3x - 15)`
`= 2x(x - 5) - 3(x - 5)`
`= (x - 5)(2x - 3)`
