* Bạn tham khảo nha >v< *
$\begin{align} & \,96\sqrt{3}\sin \dfrac{\pi }{48}\cos \dfrac{\pi }{48}\cos \dfrac{\pi }{24}\cos \dfrac{\pi }{12}\cos \dfrac{\pi }{6} \\ & =48\sqrt{3}\sin \dfrac{\pi }{24}\cos \dfrac{\pi }{24}\cos \dfrac{\pi }{12}\cos \dfrac{\pi }{6} \\ & =24\sqrt{3}\sin \dfrac{\pi }{12}\cos \dfrac{\pi }{12}\cos \dfrac{\pi }{6} \\ & =12\sqrt{3}\sin \dfrac{\pi }{6}\cos \dfrac{\pi }{6} \\ & =6\sqrt{3}\sin \dfrac{\pi }{3}=9 \\ \end{align}$