Bảo toàn nguyên tố:
$n_{CO_2}=0,1x(mol)$
$n_{H_2O}=0,05y(mol)$
$\Delta m=23g=m_{CO_2}+m_{H_2O}$
$\Rightarrow 44.0,1x+18.0,05y=23$
$\Leftrightarrow \dfrac{44x}{9}+y=\dfrac{230}{9}$
$\Leftrightarrow 44x+9y=230$
$\to x=4; y=6 (C_4H_6)$
CTCT:
$CH\equiv C-CH_2-CH_3$
$CH_3-C\equiv C-CH_3$
$CH_2=CH-CH=CH_2$
$CH_3-CH=C=CH_2$