Đáp án:
\[n_{CO_2}=\dfrac{4,4}{44}=0,1(mol)\]
\[\to n_C=0,1(mol)\]
\[\to m_C=12\times 0,1=1,2(g)\]
\[n_{H_2O}=\dfrac{0,9}{18}=0,05(mol)\]
\[\to n_H=0,05\times 2=0,1(mol)\]
\[\to m_H=0,1\times 1=0,1(mol)\]
\[m_C+m_H=m_A\to A: C, H\]
A có dạng $C_xH_y$
$\to x:y=0,1:0,1=1:1$
$\to CTTQ:{(CH)}_n$
$\to n=2$
$\to C_2H_2$